Questions with answers and explanation:
(A) 4.55
Answer:(a)
Answer(b)
Answer( a)
Answer( b)
Answer( a)
Answer;(d)
Answer:(a)
Answer.(b)
Answer(d)
Answer( a)
1.Sonu borrowed Rs. 725 from Moun at the beginning of a year at interest. After 8 months, he again borrowed Rs. 362.50 at a rate of interest double that the former sum bears. At the end of the year, the sum of interest on both loans is Rs. 43.50. Find the first rate of interest per annum.
(B) 4.75%
(C) 6.25%
(D) 7.2%
(E) None of these.
Answer:(a)
43.5= (725×R×1)/100×(362.5×4×2R)/(12×100)
43.5×300=2175R+362.5×2R
=2900 R
R=4.5
2.The cost price of goods with a bankrupt is Rs. 25500 and if the goods had realised in their full value, his creditiors would have received 85 paise in the rupee. But 2/5 of the goods were sold at 17% and the remainder at 22% below their cost price. How many paise in a rupee was received by the creditors?
(A) 72 paise
(B) 68 paise
(C) 55 paise
(D) 52 paise
(E) None of these
Answer(b)
Total debt=25500× 100/85=Rs.30000
Money received by selling the goods=25500(2/5×83/100+3/5×78/100)
=25500/500 (166+234)
=51×400=Rs.20400
Therefore, money received by the creditors for a rupee=Rs.(20400/30000)=Rs.0.68=68 paise
Hence, the creditor received 68 paise in a rupee.
3.A carpenter undertakes to supply 2000 tables at Rs. 1725 each. He estimates that if 10% are defective which will be sold at 50%, then the profit will be 15% on his whole outlay. When the tables were supplied, 70% of the tables were found defective. What loss did the carpenter incur?
(A) Rs. 607500
(B) Rs. 557500
(C) Rs. 550500
(D) Rs. 448560
(E) none of these
Answer( a)
10% of 2000=200
Selling price of 200 tables at 50%=Rs.(200×1725/2)=Rs.172500
Selling price of remaining 1800 tables=Rs.(1800×1725)=Rs.3105000
Total revenue from selling 2000 tables =Rs.(172500+3105000)=Rs.3277500
Now, Rs. 3277500 includes 15% profit. Therefore, cost price of 2000 tables=100/115×3277500=Rs.2850000
Now the actual selling price=2000×30/100×1725+2000×70/100×1725/2
=2000×1725(30/100+35/100)
=20×1725×65=Rs.2242500
∴Loss=Cost Price-Selling Price
Hence, the carpenter incurs a loss of Rs. 607500.
4.Asha invested Rs. 10,000 in a new mutual fund scheme exactly three years ago. The value of the investment increased by 10% during the first year, increased by 5% during the second year, and decreased by 10% during the third year. What is the value of the investment today?
(A) Rs. 10,500
(B) Rs. 10,395
(C) Rs. 10,342
(D) Rs. 10,230
(E) none of these
Answer( b)
The first year’s increase of 10% can be expressed as 1.10; the second year’s increase of 5% can be expressed as 1.05; and the third year’s decrease of 10% can be expressed as 0.90. Now, multiply the original value of the investment account by each of these yearly changes.
10,000×1.10×1.05×0.90=10,395
Hence, the value of the investment today is Rs. 10,395.
5.In Delhi, 60% of the registered voters are BJP-supporters and the rest are Congress-supporters. In a mayoral race, if 75% of the registered voters who are BJP-supporters and 20% of the registered voters who are Congress-supporters are expected to vote for candidate A, what percent of the registered voters are expected to vote for candidate A?
(A) 53%
(B) 55%
(C) 57%
(D) 59%
(E) none of these.
Answer( a)
Let y be the number of registered voters in Delhi. The, the information that 60% of the registered voters are from BJP can be expressed as 0.60y. From this, it can be stated that 1.00y-0.60y=0.40y are from Congress. The percentage of BJP-supporters and the percentage of Congress-supporters who are expected to vote for candidate A can then be expressed as:
0.75×0.60y+0.20×0.40y
Simplify the expression to determine the total percentage of voters expected to vote for candidate A.
0.75×0.60y+0.20×0.40y
=0.45y+0.08y=0.53y
Hence, 53% of the registered voters are expected to vote for candidate A.
6.A pharmaceutical company received Rs. 3 million in royalties on the first Rs. 20 million in sales of the generic equivalent of one of its products and then Rs.9 million in royalties on the next Rs. 108 million in royalties on the next Rs. 108 million in sales. By approximately what percent did the ratio of royalties to sales decrease from the first Rs. 20 million in sales to the next Rs. 108 million in sales?
(A) 10.27%
(B) 20.63%
(C) 38.6%
(D) 44.44%
(E) None Of these.
Answer;(d)
The ratio of royalties to sales for the first Rs. 20 million in sales is 3/20, and the ratio of royalties to sales for the next Rs. 108 million in sales is 9/108=1/12. The percent decrease in the royalties to sales ratios is 100 times the quotient of the difference in the ratios divided by the ratio of royalties to sales for the first Rs. 20 million in sales, i.e.,
(1/12-3/20)/(3/20)×100=(1/12-3/20)×20/3×100
=((5-9)/60)×20/3×100
=(-4)/60×20/3×100=(-4)/9×100
=-0.4444×100=-44.44
=44.44%decrease
7.In Chittaranjan, only two newspapers Jan Jagran and Jan Khabar are published. It is known that 25% of the city population reads Jan Jagran and 20% reads Jan Khabar while 8% reads both the newspapers. It is also known that 30% of those who read Jan Jagran but not Jan Khabar look into advertisement and 40% of those who read Jan Khabar but not Jan Jagran look into advertisement while 50% of those who read both the newspapers look into advertisements. What is the percentage of the population who read an advertisement?
(A) 13.9%
(B) 15.8%
(C) 17.2%
(D) 21.4%
(E) None of these
Answer:(a)
Let the population of the city be 100. Then,
People reading Jan Jagran=25
People reading Jan Khabar=20
People reading both=8
People reading only Jan Jagran=17
People reading only Jan Khabar=12
Therefore, required percentage of people who read an advertisement=(5.1+4.8+4)=13.9%.
8.In my office, at least 50% of the people read an e-newspaper. Among those who read an e-newspaper, at most 25% read more than one e-paper. Only one of the following statements follows from the statements given below. Which one is it?
(A) At the most 37.5% read exactly one e-paper.
(B) At least 37.5% read exactly one e-paper.
(C) At the most 19.8% read exactly one e-paper.
(D) At least 19.8% read exactly one e-paper.
(E) none of these
Answer.(b)
Let the number of people in my office=100
At least 50 people read an e-newspaper.
At most 12.5 people read more than one e-newspaper.
Therefore, at least 37.5 people read only one e-newspaper.
Hence, at least 37.5% read exactly one e-newspaper.
9.In Times Model School, 60% of the students are boys. In an aptitude test, 80% of the girls scored more than 40 marks (out of a maximum possible 150 marks). If 60% of the total students scored more than 40 marks in the same test, find the fraction of the boys who scored 40 marks or less.?
(A) 3/5
(B) 6/7
(C) 5/7
(D) 7/15
(E) none of these
Answer(d)
Let the total number of students by y. Then,
Number of boys=3y/5
Number of girls=2y/5
Number of girls scoring more than 40 marks=4/5×2y/5=8y/25
Total number of students scoring more than 40 marks=3y/5
∴ Required fraction =7/25×5/3=7/15
Hence, the fraction of the boys who scored 40 marks or less is 7/15.
10.In a recent opinion poll held during April, 60% of the respondents favoured India Against Corruption (IAC) while the rest favoured Indian political parties (IPP). It was found in May polls that 10% of IAC supporters switched their preference to IPP, while the same percentage of IPP’s supporters also switched their preference to IAC. What percentage of the electorate should now switch their preference from IAC to IPP so that they are at par?
(A) 14%
(B) 19%
(C) 24%
(D) 29%
(E) 22%
Answer( a)
Let the total number of respondents=100
People favoured IAC=60
People favoured IPP=40
New no. of people facouring IAC=58
New no. of people favouring IPP=42
Required percentage= (58-50)*100/58=14%Approx
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